SQL>SELECT e.ename, d.dname
FROM emp e , dept d
WHERE e.deptno = d.deptno;
- WHERE 절에 조인 조건을 작성하고 column명 앞에 테이블명을 적습니다.
'(BETWEEN AND, IS NULL, IS NOT NULL, IN, NOT IN)'
SQL>SELECT e.ename, d.dname
FROM emp e, dept d
WHERE e.sal BETWEEN 3000 AND 4000;
ENAME DNAME
----------------- -----------
SCOTT ACCOUNTING
FORD ACCOUNTING
SCOTT RESEARCH
FORD RESEARCH
-- INNER JOIN을 사용한 문장 SQL> SELECT e.empno, e.ename FROM dept d INNER JOIN emp e ON d.deptno=e.deptno; -- 일반적인 SQL 문장 SQL> SELECT e.empno, e.ename FROM dept d , emp e WHERE d.deptno=e.deptno; EMPNO ENAME -------------- 7369 SMITH 7499 ALLEN 7521 WARD 7566 JONES 7654 MARTIN 7698 BLAKE 7782 CLARK 7788 SCOTT 7839 KING 7844 TURNER 7876 ADAMS 7900 JAMES 7902 FORD 7934 MILLER (14 rows)
'LEFT OUTER JOIN' , 'RIGHT OUTER JOIN', 'FULL OUTER JOIN'를 지원 합니다.'OUT조인 조건이 걸려있는 테이블에는 다른 조건절이 들어와도 똑같이 OUT조인 연산자인 (+)를 해주어야 합니다.'예제1) 일반 조인의 경우
SQL> SELECT DISTINCT(a.deptno), b.deptno
FROM emp a, dept b
WHERE a.deptno = b.deptno
DEPTNO DEPTNO
---------- ----------
10 10
20 20
30 30
예제2) out join을 했을 경우
SQL> SELECT DISTINCT(a.deptno), b.deptno
FROM emp a, dept b
WHERE a.deptno(+) = b.deptno
DEPTNO DEPTNO
------- ----------
10 10
20 20
30 30
40
※ 다음의 쿼리를 한번 잘 보시기 바랍니다.
SQL> SELECT DISTINCT(a.deptno), b.deptno
FROM emp a, dept b
WHERE a.deptno(+) = b.deptno
AND a.ename LIKE '%%%';
DEPTNO DEPTNO
---------- ----------
10 10
20 20
30 30
쿼리 결과를 잘 보면 out조인이 되지 않은 것을 알 수 있습니다.
위 쿼리를 out조인이 되기 위해서는 아래와 같이 고쳐야 합니다.
SQL> SELECT DISTINCT(a.deptno), b.deptno
FROM emp a, dept b
WHERE a.deptno(+) = b.deptno
AND a.ename(+) LIKE '%%%'
DEPTNO DEPTNO
---------- ----------
10 10
20 20
30 30
40
OUT조인 조건이 걸려있는 테이블에는 다른 조건절이 들어와도 똑같이 OUT조인 연산자인 (+)를 해주어야 합니다.
SQL> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
-------------------------------------------------------------------------
7369 SMITH CLERK 7902 1980-12-17 800 20
7499 ALLEN SALESMAN 7698 1981-02-20 1600 300 30
7521 WARD SALESMAN 7698 1981-02-22 1250 500 30
7566 JONES MANAGER 7839 1981-04-02 2975 20
7654 MARTIN SALESMAN 7698 1981-09-28 1250 1400 30
7698 BLAKE MANAGER 7839 1981-05-01 2850 30
7782 CLARK MANAGER 7839 1981-06-09 2450 10
7788 SCOTT ANALYST 7566 1987-04-19 3000 20
7839 KING PRESIDENT 1981-11-17 5000 10
7844 TURNER SALESMAN 7698 1981-09-08 1500 0 30
7876 ADAMS CLERK 7788 1987-05-23 1100 20
7900 JAMES CLERK 7698 1981-12-03 950 30
7902 FORD ANALYST 7566 1981-12-03 3000 20
7934 MILLER CLERK 7782 1982-01-23 1300 10
(14 rows)
SQL> create table empinfo as
select deptno,count(1) as count from emp group by deptno;
SQL> insert into empinfo values (50,1);
SQL> select * from empinfo;
DEPTNO COUNT
--------------
30 6
20 5
10 3
50 1
(4 rows)
SQL> select * from dept;
DEPTNO DNAME LOC
--------------------------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
(4 rows)
1. 왼쪽 테이블에 조인시킬 컬럽의 값이 없는 경우 사용합니다.
SQL> SELECT e.deptno, d.deptno
FROM empinfo e LEFT OUTER JOIN dept d ON e.deptno = d.deptno;
DEPTNO DEPTNO_1
----------------
30 30
20 20
10 10
50
SQL> SELECT e.deptno, d.deptno
FROM empinfo e RIGHT OUTER JOIN dept d ON e.deptno = d.deptno;
DEPTNO DEPTNO_1
----------------
30 30
20 20
10 10
40
SQL> SELECT e.deptno, d.deptno
FROM empinfo e FULL OUTER JOIN dept d ON e.deptno = d.deptno;
DEPTNO DEPTNO_1
----------------
30 30
20 20
10 10
50
40
SQL> SELECT concat(a.ename,' ') ||' : \'|| b.sal 급여
FROM emp a, emp b
WHERE a.empno = b.empno;
급여
-------------------
SMITH : \800
ALLEN : \1600
WARD : \1250
JONES : \2975
MARTIN : \1250
BLAKE : \2850
CLARK : \2450
SCOTT : \3000
이름과 급여를 연결시켜서 보여줍니다.
SQL> SELECT ename FROM emp CROSS JOIN dept order by ename; ENAME ------ ADAMS ADAMS ADAMS ADAMS ALLEN ALLEN ALLEN ALLEN BLAKE BLAKE BLAKE BLAKE CLARK CLARK CLARK CLARK FORD FORD FORD FORD JAMES JAMES JAMES JAMES JONES JONES JONES JONES KING KING KING KING MARTIN MARTIN MARTIN MARTIN MILLER MILLER MILLER MILLER SCOTT SCOTT SCOTT SCOTT SMITH SMITH SMITH SMITH TURNER TURNER TURNER TURNER WARD WARD WARD WARD (56 rows)
-- NATURAL JOIN을 사용한 SQL 문장. SQL> SELECT empno, ename, deptno FROM emp NATURAL JOIN dept; -- Oracle9i 이전에 일반적인 SQL 문장 SQL> SELECT e.empno, e.ename, d.deptno FROM emp e, dept d WHERE e.deptno=d.deptno;
-- 일반적인 사용 방법 SQL> SELECT e.empno, e.ename, deptno FROM emp e JOIN dept d USING(deptno)
-- 테스트를 위해 scott유저에서 아래 insert문장을 실행시켜 주세요.
SQL> INSERT INTO bonus(ename, job, sal) VALUES('SMITH','CLERK',500);
-- ON절 사용 예제 (multi-table joins)
SQL> SELECT e.empno, e.ename, e.sal
FROM emp e JOIN dept d ON (e.deptno=d.deptno)
JOIN bonus b ON (b.ename = e.ename)
WHERE e.sal IS NOT NULL;
EMPNO ENAME SAL
-----------------
7369 SMITH 800